If the absolute magnitude, M, of a supernova is −19 and a galaxy is found that contains a supernova with an apparent magnitude, m, of 16. What is the distance to the galaxy Hint: dpc = $10^{(m - M + 5)/5}$
A)100 AU
B)100 pc
C)100 ly
D)100 kpc
E)100 Mpc

Question

Quizplus · Accepted Answer

Using the distance modulus formula: $d_{pc} = 10^{(m - M + 5)/5}$, substituting m = 16 and M = -19 gives $d_{pc} = 10^{(16 + 19 + 5)/5} = 10^{8} = 100,000,000$ pc, which is 100 Mpc.

If the Absolute Magnitude, M, of a Supernova Is −19 10(m−M+5)/510^{(m - M + 5)/5}10(m−M+5)/5

If the Absolute Magnitude, M, of a Supernova Is −19 $10^{(m - M + 5)/5}$