What is the osmolarity of a solution containing 3 M MgCl₂ and 2 M glucose?

Question

Quizplus · Accepted Answer

To calculate the osmolarity of the solution, we need to find the total number of particles in the solution. 
For MgCl₂, each molecule will dissociate into 3 particles (1 Mg²⁺ and 2 Cl⁻ ions). 
For glucose, it will remain as 1 particle. 
Total number of particles = (3 M MgCl₂ x 3) + (2 M glucose x 1) 
= 9 + 2 
= 11 
Therefore, the osmolarity of the solution is 11 OsM.

What Is the Osmolarity of a Solution Containing 3 M