A Carnot engine has a heat input of 3700 J and heat exhaust of 1400 J.What is the ratio of the Kelvin temperature of the hot reservoir to that of the cold reservoir,T_H/T_C?

Question

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by 1 - (Q_c/Q_h) = 1 - (1400/3700). This efficiency is also equal to 1 - (T_c/T_h), so T_h/T_c = Q_h/Q_c = 3700/1400 = 2.64, which is approximately 2.6.

A Carnot Engine Has a Heat Input of 3700 J