Vibrations with frequency 6.00 × 10² Hz are established on a 1.33-m length of string that is clamped at both ends.The speed of waves on the string is 4.00 × 10² m/s.
-How far from either end of the string does the first node occur?
A)0.17 m
B)0.33 m
C)0.49 m
D)0.66 m
E)0.75 m

Question

Quizplus · Accepted Answer

The wavelength (λ) is calculated using the formula v = fλ, where v is the speed and f is the frequency. λ = v/f = (4.00 × 10² m/s) / (6.00 × 10² Hz) = 0.67 m. The first node occurs at λ/2 from either end, which is 0.67 m / 2 = 0.33 m.

Vibrations with Frequency 6