An uncharged 5.0-µF capacitor and a resistor are connected in series to a 12-V battery and an open switch to form a simple RC circuit.The switch is closed at t = 0 s.The time constant of the circuit is 4.0 s.
-Determine the maximum charge on the capacitor.

Question

Quizplus · Accepted Answer

The maximum charge on the capacitor, $Q$, can be calculated using the formula $Q = C \times V$, where $C$ is the capacitance (5.0 µF) and $V$ is the voltage (12 V). Converting µF to F (1 µF = $10^{-6}$ F), we get $Q = 5.0 \times 10^{-6} \, \text{F} \times 12 \, \text{V} = 6.0 \times 10^{-5} \, \text{C}$.

An Uncharged 5