A scuba diver shines a flashlight from beneath the surface of water (n = 1.33)such that the light strikes the water-air boundary with an angle of incidence of 37°.At what angle is the beam refracted?
A)31°
B)53°
C)48°
D)65°
E)90°

Question

Quizplus · Accepted Answer

Using Snell's Law: 
n1sinθ1 = n2sinθ2 
where n1 is the refractive index of the initial medium (water), θ1 is the angle of incidence, n2 is the refractive index of the second medium (air), and θ2 is the angle of refraction. 
Plugging in the values, we get: 
1.33sin37° = sinθ2 
θ2 ≈ 53° 
Therefore, the answer is choice B.

A Scuba Diver Shines a Flashlight from Beneath the Surface