Determine the energy of a single photon in a monochromatic beam of light of wavelength 625 nm.
A)1.99 eV
B)2.08 eV
C)2.32 eV
D)3.49 eV
E)4.77 eV

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the equation $E = \frac{hc}{\lambda}$, where $E$ is the energy of the photon, $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{m}^2 \, \text{kg} / \text{s}$), $c$ is the speed of light in a vacuum ($3.00 \times 10^8 \, \text{m/s}$), and $\lambda$ is the wavelength of the light in meters. Converting 625 nm to meters gives $625 \times 10^{-9} \, \text{m}$. Plugging these values into the equation gives $E = \frac{(6.626 \times 10^{-34} \, \text{m}^2 \, \text{kg} / \text{s})(3.00 \times 10^8 \, \text{m/s})}{625 \times 10^{-9} \, \text{m}}$. This calculation results in an energy value in joules, which can then be converted to electron volts (eV) using the conversion factor $1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J}$. The calculated energy is approximately 1.99 eV.

Determine the Energy of a Single Photon in a Monochromatic