Photons of what minimum frequency are required to remove electrons from gold? Note: The work function for gold is 4.8 eV.
A)7.3 × 10¹⁴ Hz
B)1.2 × 10¹⁵ Hz
C)3.8 × 10¹⁷ Hz
D)6.5 × 10¹⁵ Hz
E)4.6 × 10¹⁴ Hz

Question

Quizplus · Accepted Answer

The minimum frequency required to remove an electron from an atom is given by the equation:

ν = (Φ/h) + (KE/h)

where ν is the frequency of the photon, Φ is the work function of the metal, h is Planck's constant, and KE is the kinetic energy of the emitted electron.

To find the minimum frequency required to remove an electron from gold, we need to solve for ν when KE = 0:

ν = Φ/h = (4.8 eV)/(4.14 x 10^-15 eV s) = 1.16 x 10^15 Hz

Therefore, the minimum frequency required to remove electrons from gold is 1.2 x 10^15 Hz. The answer is B.

Photons of What Minimum Frequency Are Required to Remove Electrons