Approximately,what is the de Broglie wavelength of an electron that has been accelerated through a potential difference of 225 V? The mass of an electron is 9.11 × 10^-³¹ kg. A)0.14 nm B)0.082 nm C)0.043 nm D)0.0092 nm E)0.22 nm

Question

Quizplus · Accepted Answer

The de Broglie wavelength (λ) of an electron can be calculated using the following formula:

λ = h / p

where h is the Planck's constant and p is the momentum of the electron.

The momentum of the electron can be calculated using the following formula:

p = √(2mE)

where m is the mass of the electron, E is the potential difference through which it has been accelerated.

Substituting the given values,

p = √(2 x 9.11 x 10^-31 kg x 225 V)

p = 5.72 x 10^-23 kg m/s

Substituting this value of momentum,

λ = h / p

λ = 6.63 x 10^-34 J s / (5.72 x 10^-23 kg m/s)

λ = 1.16 x 10^-10 m

λ = 0.116 nm

Therefore, the best answer choice is B, which is the closest to the calculated value.

Approximately,what Is the De Broglie Wavelength of an Electron That