Case 1 You have just starting working at Quantum Company. As a new programmer, you have been asked to review and correct various pseudocode. -The following pseudocode checks if an item number is valid: start Declarations Num sub = 0 Num SIZE = 5 Num VALID_ITEM [5] = 27,53,84,89,95 String foundIt = "N" Input item While sub

Question

Case 1

You have just starting working at Quantum Company. As a new programmer, you have been asked to review and correct various pseudocode.

-The following pseudocode checks if an item number is valid: start
Declarations
Num sub = 0
Num SIZE = 5
Num VALID_ITEM [5] = 27,53,84,89,95
String foundIt = "N"
Input item
While sub < SIZE
If item = VALID_ITEM[sub] then
FoundIt = "Y"
Endif
Sub = sub +1
Endwhile
If foundIt = "Y" then
Output "Valid item number"
Else
Output "Invalid item number"
Endif
Stop
Which while loop makes this more efficient?
A) while sub < SIZE AND foundIt = "N"
B) while sub < SIZE AND foundIt > "N"
C) while sub < SIZE AND foundIt = "Y"
D) The while loop is already efficient

Quizplus · Accepted Answer

In this pseudocode, the while loop with the condition "while sub < SIZE AND foundIt = "N"" makes the code more efficient. This is because it checks both conditions at the same time, and as soon as the item number is found, the loop will stop, which saves unnecessary iterations through the array. If the loop continued to execute after the item was found, it would waste processing time and reduce efficiency. Therefore, it is best to use the loop that stops as soon as it finds the item.

Case 1 You Have Just Starting Working at Quantum Company. as a Company