The unit improvement factor for an 80% learning curve at 100 units is 0.2271.The first and second timings of a person doing a job are 20 minutes and 16 minutes respectively,what is the learning-adjusted time estimate for unit number 100?
A)20 minutes
B)16 minutes
C)2.271 minutes
D)4.542 minutes
E)0.800 minutes

Question

Quizplus · Accepted Answer

The learning curve equation is given as: 
C = a * N^b

where 
C = Time taken to complete the unit 
N = Unit number 
a = time taken to complete the first unit 
b = log(learning rate)/log(2)

Given, 
a = 20 minutes (time taken to complete the first unit)
learning rate = 80% 
N = 100 (unit number) 
Unit improvement factor = 0.2271

Using the formula for b, we get:
b = log(0.80)/log(2) = -0.3219

Substituting the given values in the learning curve equation, we get:
C = 20 * 100^(-0.3219) = 4.542 minutes (time taken to complete the 100th unit)

Therefore, the learning-adjusted time estimate for unit number 100 is 4.542 minutes. The best choice is D.

The Unit Improvement Factor for an 80% Learning Curve at 100