What is the empirical formula of a compound that is 62.0% C,10.4% H,and 27.5% O by mass?

Name: What is the empirical formula of a compound that is 62.0% C,10.4% H,and 27.5% O by mass?
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Quizplus · Accepted Answer

To find the empirical formula, convert the percentages to moles: C: 62.0 g / 12.01 g/mol = 5.16 mol, H: 10.4 g / 1.008 g/mol = 10.32 mol, O: 27.5 g / 16.00 g/mol = 1.72 mol. Divide each by the smallest number of moles (1.72) to get the ratio: C: 3, H: 6, O: 1, which gives the empirical formula C₃H₆O.

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