How many millilitres of 0.132 mol L^-1 HClO₄ solution are needed to neutralize 50.00 mL of 0.0789 mol L^-1 NaOH?

Name: How many millilitres of 0.132 mol L -1 HClO 4 solution are needed to neutralize 50.00 mL of 0.0789 mol L -1 NaOH?
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Question

Quizplus · Accepted Answer

To neutralize NaOH with HClO4, use the formula: (C1)(V1) = (C2)(V2). Here, C1 = 0.132 mol/L, C2 = 0.0789 mol/L, and V2 = 50.00 mL. Solving for V1 gives V1 = (0.0789 mol/L * 50.00 mL) / 0.132 mol/L = 29.9 mL.

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