A stock solution of HNO₃ is prepared and found to contain 13.5 mol L^-1 of HNO₃. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, what is the concentration of the diluted solution?

Question

Quizplus · Accepted Answer

To find the concentration of the diluted solution, we can use the formula:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
From the problem, we know that:
M1 = 13.5 mol/L
V1 = 25.0 mL = 0.0250 L
V2 = 0.500 L
Solving for M2:
M2 = M1V1/V2 = (13.5 mol/L)(0.0250 L)/(0.500 L) = 0.675 mol/L
Therefore, the concentration of the diluted solution is 0.675 mol/L. The best choice is C.

A Stock Solution of HNO3 Is Prepared and Found to Contain

A Stock Solution of HNO₃ Is Prepared and Found to Contain