Using the following equation for the combustion of octane, calculate the amount of grams of carbon dioxide formed from 100.0 g of octane. The molar mass of octane is 114.33 g mol^-1. The molar mass of carbon dioxide is 44.0095 g mol^-1. 2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O Δ_rH°= -11018 kJ

Question

Quizplus · Accepted Answer

1. Calculate the moles of octane:

100.0 g / 114.33 g/mol = 0.8743 mol octane

2. Calculate the moles of carbon dioxide produced using stoichiometry:

0.8743 mol octane x (16 mol CO2 / 2 mol octane) = 6.9944 mol CO2

3. Convert moles to grams:

6.9944 mol CO2 x 44.0095 g/mol = 307.9 g CO2

Therefore, the amount of grams of carbon dioxide formed from 100.0 g of octane is 307.9 g, which is option B.

Using the Following Equation for the Combustion of Octane, Calculate