Use the ΔfH° and ΔrH° information provided to calculate ΔfH° for IF: ΔfH° (kJ mol-1) IF7(g) + I2(g) → IF5(g) + 2IF(g) ΔrH° = -89 kJ
IF7(g) -941
IF5(g) -840
A) 101 kJ mol-1
B) -146 kJ mol-1
C) -190. kJ mol-1
D) -95 kJ mol-1
E) 24 kJ mol-1
Correct Answer:
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