The rate of disappearance of HBr in the gas phase reaction 2HBr(g) → H₂ (g) + Br₂ (g)
Is 0.130 mol L^-1 s^-1 at 150 °C. The rate of reaction is ________ mol L^-1 s^-1.

Question

The rate of disappearance of HBr in the gas phase reaction 2HBr(g)→ H₂ (g)+ Br₂ (g) Is 0.130 mol L^-1 s^-1 at 150 °C. The rate of reaction is ________ mol L^-1 s^-1.

Quizplus · Accepted Answer

The balanced equation for the reaction is:
2 HBr(g) → H2(g) + Br2(g)

The rate of disappearance of HBr is given as 0.130 mol L-1 s-1, which means that the rate of the reaction is half of that, since 2 mol of HBr is consumed in the reaction.
Rate of reaction = 0.130/2 = 0.0650 mol L-1 s-1
Therefore, the answer is B.

The Rate of Disappearance of HBr in the Gas Phase