Hydrogen iodide decomposes at 800 K via a second-order process to produce hydrogen and iodine according to the following chemical equation: 2HI(g) → H2(g) + I2(g)
At 800 K it takes 142 seconds for the initial concentration of HI to decrease from 6.75 × 10-2 mol L-1 to 3.50 × 10-2 mol L-1. What is the rate constant for the reaction at this temperature?
A) 5.12 × 10-4 L mol-1 s-1
B) 9.69 × 10-2 L mol-1 s-1
C) 10.3 L mol-1 s-1
D) 1.95 × 103 L mol-1 s-1
Correct Answer:
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