Determine the [OH⁻] concentration in a 0.169 mol L^-1 Ca(OH)₂ solution. A) 0.338 mol L^-1 B) 0.169 mol L^-1 C) 5.92 × 10^-14 mol L^-1 D) 2.96 × 10^-14 mol L^-1 E) 0.298 mol L^-1

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Quizplus · Accepted Answer

Calcium hydroxide, Ca(OH)₂, dissociates into one Ca²⁺ ion and two OH⁻ ions. Therefore, the concentration of OH⁻ ions is twice the concentration of Ca(OH)₂. Thus, [OH⁻] = 2 × 0.169 mol L⁻¹ = 0.338 mol L⁻¹.

Determine the [OH⁻] Concentration in a 0