Determine the pOH of a 0.116 mol L^-1 Ba(OH)₂ solution at 25 °C. A) 8.62 B) 13.06 C) 13.37 D) 0.63 E) 12.56

Name: Determine the pOH of a 0.116 mol L -1 Ba(OH) 2 solution at 25 °C. A) 8.62 B) 13.06 C) 13.37 D) 0.63 E) 12.56
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Quizplus · Accepted Answer

Ba(OH)₂ dissociates into Ba²⁺ and 2 OH⁻ ions. Therefore, the concentration of OH⁻ is 2 × 0.116 mol L⁻¹ = 0.232 mol L⁻¹. The pOH is calculated as -log[OH⁻] = -log(0.232) ≈ 0.63.

Determine the POH of a 0