Determine the molar solubility of CaSO₄ in a solution containing 0.100 mol L^-1 Na₂SO₄. K_sp (CaSO₄) = 2.4 × 10^-5. A) 4.9 × 10^-3 mol L^-1 B) 2.4 × 10^-4 mol L^-1 C) 5.8 × 10^-10mol L^-1 D) 1.2 × 10^-5 mol L^-1 E) 0.10 mol L^-1

Question

Quizplus · Accepted Answer

The solubility product constant (Ksp) expression for CaSOS1U1B14S1U1B0 is:

CaSOS1U1B14S1U1B0(s) ⇌ Ca2+(aq) + SOS1U1B14S1U1B0 2-(aq)

Ksp = [Ca2+][SOS1U1B14S1U1B0 2-]

The balanced equation shows that [Ca2+] and [SOS1U1B14S1U1B0 2-] are equal in magnitude. Let x be the molar solubility of CaSOS1U1B14S1U1B0 in the given solution. Then:

Ksp = x2

2.4 × 10S1U1P1-5S1S1P0 = x2

x = 2.4 × 10S1U1P1-5/2 mol LS1U1P1-1S1S1P0 = 1.2 × 10S1U1P1-5S1S1P0 mol LS1U1P1-1S1S1P0

The closest answer choice is B, which is 2.4 × 10S1U1P1-4S1S1P0 mol LS1U1P1-1S1S1P0. However, this is only half the actual answer because the question asks for the molar solubility of CaSOS1U1B14S1U1B0, whereas the calculated value is for [Ca2+] and [SOS1U1B14S1U1B0 2-]. Therefore, the correct answer is 1.2 × 10S1U1P1-5S1S1P0 mol LS1U1P1-1S1S1P0 of CaSOS1U1B14S1U1B0.

Determine the Molar Solubility of CaSO4 in a Solution Containing

Determine the Molar Solubility of CaSO₄ in a Solution Containing