Determine the molar solubility of PbSO₄ in pure water. K_sp (PbSO₄) = 1.82 × 10^-8. A) 1.82 × 10^-8 mol L^-1 B) 1.35 × 10^-4 mol L^-1 C) 9.10 × 10^-9 mol L^-1 D) 3.31 × 10^-16 mol L^-1 E) 4.48 × 10^-4 mol L^-1

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Quizplus · Accepted Answer

The molar solubility of PbS in water can be calculated using the solubility product expression: K_sp = [PbS][S2-] Assuming that x mol L-1 of PbS will dissolve in water, then the equilibrium concentrations will be [PbS] = x mol L-1 and [S2-] = x mol L-1. Substituting these values into the solubility product expression gives: 1.82 × 10^-8 = x * x x = 1.35 × 10^-4 mol L-1 Therefore, the molar solubility of PbS in water is 1.35 × 10^-4 mol L-1.

Determine the Molar Solubility of PbSO4 in Pure Water

Determine the Molar Solubility of PbSO₄ in Pure Water