How many Zn atoms are contained in 922 g of Zn? A) 5.90 × 10²⁵ Zn atoms B) 7.09 × 10²¹ Zn atoms C) 8.49 × 10²⁴Zn atoms D) 4.27 × 10²² Zn atoms E) 4.18 × 10²⁴ Zn atoms

Question

Quizplus · Accepted Answer

To solve this problem, we need to use the mole concept and Avogadro's number.

1. Find the molar mass of Zn from the periodic table: 65.38 g/mol

2. Convert the given mass of Zn to moles:

922 g Zn x (1 mol Zn / 65.38 g Zn) = 14.1 mol Zn

3. Use Avogadro's number to convert moles of Zn to number of Zn atoms:

14.1 mol Zn x (6.022 x 10^23 atoms/mol) = 8.49 x 10^24 Zn atoms

Therefore, the answer is C, 8.49 × 10^24 Zn atoms.

How Many Zn Atoms Are Contained in 922 G of Zn