Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. DH°(kJ)
Ca(s) → Ca(g) 193
Ca(g) → Ca⁺(g) + e⁻ 590.
2 O(g) → O2(g) -498
O(g) + e⁻ → O⁻(g) -141
O⁻(g) + e⁻ → O2⁻(g) 878
Ca(s) +
O2(g) → CaO(s) -635
Ca2⁺(g) + O2⁻(g) → CaO(s) -3414
A) 1010 kJ
B) 1757 kJ
C) 1508 kJ
D) -3027 kJ
E) -1514 kJ
Correct Answer:
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