What is the empirical formula for a compound that is composed of 53.91% carbon.35.91% oxygen,and 10.17% hydrogen? A) CHO B) C₄H₉O₂ C) C₂H₄O₃ D) CH₂O₂ E) C₃H₆O

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To find the empirical formula, convert the percentages to moles: C: 53.91 g / 12.01 g/mol = 4.49 mol, H: 10.17 g / 1.01 g/mol = 10.07 mol, O: 35.91 g / 16.00 g/mol = 2.24 mol. Divide by the smallest number of moles (2.24) to get the ratio: C: 2, H: 4.5, O: 1. Multiply by 2 to get whole numbers: C: 4, H: 9, O: 2, which corresponds to C₄H₉O₂.

What Is the Empirical Formula for a Compound That Is