How many oxygen atoms are there in 3.00 g of sodium dichromate,Na₂Cr₂O₇?

Question

Quizplus · Accepted Answer

First, calculate the molar mass of Na₂Cr₂O₇, which is approximately 261.97 g/mol. Then, find the moles of Na₂Cr₂O₇ in 3.00 g: 3.00 g / 261.97 g/mol = 0.01145 mol. Since there are 7 oxygen atoms per formula unit, multiply the moles by Avogadro's number (6.022 × 10²³) and by 7 to find the number of oxygen atoms: 0.01145 mol × 6.022 × 10²³ × 7 = 4.83 × 10²² oxygen atoms.

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