Determine the electron geometry,molecular geometry and polarity of HBrO₂.

Question

Quizplus · Accepted Answer

The central atom in HBrOSB12S is sulfur (S). It has four bonding pairs and one non-bonding pair of electrons, giving it a tetrahedral electron geometry (eg). However, due to the non-bonding pairs, the molecular geometry (mg) is bent. Additionally, the molecule is polar due to the asymmetrical arrangement of atoms and the polar covalent bonds between S and Br and between S and O. Therefore, the best choice is C, where the eg is tetrahedral, the mg is bent, and the molecule is polar.

Determine the Electron Geometry,molecular Geometry and Polarity of HBrO2

Determine the Electron Geometry,molecular Geometry and Polarity of HBrO₂