How many molecules of HCl are formed when 90.0 g of water reacts according to the following balanced reaction? Assume excess ICl₃.
2 ICl₃ + 3 H₂O → ICl + HIO₃ + 5 HCl

Question

How many molecules of HCl are formed when 90.0 g of water reacts according to the following balanced reaction? Assume excess ICl₃. 2 ICl₃ + 3 H₂O → ICl + HIO₃ + 5 HCl

Quizplus · Accepted Answer

The molar mass of water (H₂O) is 18.0 g/mol. Therefore, 90.0 g of water is 5.00 moles. According to the balanced equation, 3 moles of water produce 5 moles of HCl. Thus, 5.00 moles of water will produce (5/3) * 5.00 = 8.33 moles of HCl. Since 1 mole of any substance contains 6.022 × 10²³ molecules, 8.33 moles of HCl will contain 8.33 × 6.022 × 10²³ = 5.00 × 10²⁴ molecules of HCl.

How Many Molecules of HCl Are Formed When 90