How many molecules of sucrose (C₁₂H₂₂O₁₁,molar mass = 342.30 g/mol)are contained in 14.3 mL of 0.140 M sucrose solution? A)8.29 × 10²² molecules C₁₂H₂₂O₁₁ B)1.21 × 10²¹ molecules C₁₂H₂₂O₁₁ C)6.15 × 10²² molecules C₁₂H₂₂O₁₁ D)1.63 × 10²³ molecules C₁₂H₂₂O₁₁ E)5.90× 10²⁴ molecules C₁₂H₂₂O₁₁

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Quizplus · Accepted Answer

To find the number of molecules, first calculate the moles of sucrose using the formula: moles = molarity × volume (in liters). For 14.3 mL (0.0143 L) of 0.140 M solution, moles = 0.140 × 0.0143 = 0.002002 moles. Then, multiply by Avogadro's number (6.022 × 10^23 molecules/mol) to find the number of molecules: 0.002002 × 6.022 × 10^23 = 1.21 × 10^21 molecules.

How Many Molecules of Sucrose (C12H22O11,molar Mass = 342

How Many Molecules of Sucrose (C₁₂H₂₂O₁₁,molar Mass = 342