How much heat energy is required to raise the temperature of 0.298 mole of water from 35.93°C to 79.84°C? The specific heat capacity of water = 4.18 J/g°C.

Question

Quizplus · Accepted Answer

The correct answer is C because the heat energy required to raise the temperature of 0.298 mole of water from 35.93°C to 79.84°C can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Plugging in the given values, we get Q = (0.298 mole * 18.015 g/mole) * (4.18 J/g°C) * (79.84°C - 35.93°C) = 985 J.

How Much Heat Energy Is Required to Raise the Temperature