Calculate the energy that is required to change 50.0 g ice at -30.0°C to a liquid at 73.0°C.The heat of fusion = 333 J/g,the heat of vaporization = 2256 J/g,and the specific heat capacities of ice = 2.06 J /gK and liquid water = 4.184 J /gK.

Question

Quizplus · Accepted Answer

The correct answer is A because the energy required to change 50.0 g ice at -30.0°C to a liquid at 73.0°C is 3.50 × 10^4 J. This is calculated by using the following equation:Energy = (mass of ice) × (heat of fusion) + (mass of ice) × (specific heat capacity of ice) × (change in temperature) + (mass of ice) × (heat of vaporization) + (mass of ice) × (specific heat capacity of liquid water) × (change in temperature)= (50.0 g) × (333 J/g) + (50.0 g) × (2.06 J/gK) × (0°C - (-30.0°C)) + (50.0 g) × (2256 J/g) + (50.0 g) × (4.184 J/gK) × (73.0°C - 0°C)= 3.50 × 10^4 J

Calculate the Energy That Is Required to Change 50