The Henry's Law constant of methyl bromide,CH₃Br,is k = 0.159 mol/(L ∙ atm)at 25°C.What is the solubility of methyl bromide in water at 25°C and at a partial pressure of 270.mm Hg? A)0)0 565 mol/L B)0)3 55 mol/L C)0)4 48 mol/L D)42.9 mol/L

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Quizplus · Accepted Answer

The solubility is calculated using Henry's Law: S = k * P. Convert 270 mm Hg to atm (270 mm Hg / 760 mm Hg/atm = 0.355 atm) and multiply by the constant (0.159 mol/(L ∙ atm)) to get 0.0565 mol/L.

The Henry's Law Constant of Methyl Bromide,CH3Br,is K = 0

The Henry's Law Constant of Methyl Bromide,CH₃Br,is K = 0