At room temperature and 1 atm,the vapor pressure of isobutyl benzoate is 237 mm Hg,and the vapor pressure of vinyl acetate is 72.5 mm Hg.What is the total vapor pressure over a solution composed of these two substances when X_isobutylbenzoate = 0.850. A) 212 mm Hg B) 118 mm Hg C) 97.2 mm Hg D) 146 mm Hg

Question

Quizplus · Accepted Answer

The total vapor pressure can be calculated using Raoult's Law: P_total = (X_isobutyl benzoate * P_isobutyl benzoate) + (X_vinyl acetate * P_vinyl acetate). Here, X_vinyl acetate = 1 - X_isobutyl benzoate = 0.150. So, P_total = (0.850 * 237 mm Hg) + (0.150 * 72.5 mm Hg) = 201.45 mm Hg + 10.875 mm Hg = 212.325 mm Hg, which rounds to 212 mm Hg.

At Room Temperature and 1 Atm,the Vapor Pressure of Isobutyl