Given the following rate law,how does the rate of reaction change if the concentration of Y is doubled?
Rate = k [X]2[Y]3
A) The rate of reaction will increase by a factor of 5.
B) The rate of reaction will increase by a factor of 2.
C) the rate of reaction will increase by a factor of 8.
D) The rate of reaction will increase by a factor of 3.
E) The rate of reaction will remain unchanged.
Correct Answer:
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