The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C: CO(g) + Cl₂(g) → COCl₂(g)
In an equilibrium mixture of the three gases,P_CO = = 4.44 × 10^-4 atm.The partial pressure of the product,phosgene (COCl₂) ,is ________ atm.

Question

The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C: CO(g) + Cl₂(g) → COCl₂(g)
In an equilibrium mixture of the three gases,P_CO =

The K<sub>p</sub> for the reaction below is 1.49 × 10<sup>8</sup> at 100.0°C: CO(g) + Cl<sub>2</sub>(g) → COCl<sub>2</sub>(g) In an equilibrium mixture of the three gases,P<sub>CO</sub> = = 4.44 × 10<sup>-4</sup> atm.The partial pressure of the product,phosgene (COCl<sub>2</sub>) ,is ________ atm. A) 2.94 × 10<sup>1</sup> B) 7.56 × 10<sup>14</sup> C) 1.32 × 10<sup>-15</sup> D) 6.62 × 10<sup>4</sup> E) 3.33 × 10<sup>11</sup>

= 4.44 × 10^-4 atm.The partial pressure of the product,phosgene (COCl₂) ,is ________ atm.

Quizplus · Accepted Answer

The Answer of The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C: CO(g)+ Cl₂(g)→ COCl₂(g) In an equilibrium mixture of the three gases,P_CO = = 4.44 × 10^-4 atm.The partial pressure of the product,phosgene (COCl₂),is ________ atm.

The Kp for the Reaction Below Is 1

The K_p for the Reaction Below Is 1