Determine the molar solubility of Fe(OH)₂in pure water.K_sp for Fe(OH)₂= 4.87 × 10^-17. A) 2.44 × 10^-17 M B) 1.62× 10^-17 M C) 4.03 × 10^-9 M D) 3.65 × 10^-6 M E) 2.30 × 10^-6 M

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The molar solubility of Fe(OH)2 in pure water can be calculated using the Ksp expression:Ksp = [Fe2+][OH-]24.87 × 10^-17 = [Fe2+][OH-]2Assuming that the molar solubility of Fe(OH)2 is x, then:[Fe2+] = x[OH-] = 2xSubstituting these values into the Ksp expression, we get:4.87 × 10^-17 = x(2x)24.87 × 10^-17 = 4x3x3 = 1.2175 × 10^-17x = 2.30 × 10^-6 MTherefore, the molar solubility of Fe(OH)2 in pure water is 2.30 × 10^-6 M.

Determine the Molar Solubility of Fe(OH)2 in Pure Water

Determine the Molar Solubility of Fe(OH)₂in Pure Water