Determine the molar solubility for Al(OH)₃ in pure water.K_sp for Al(OH)₃ = 1.3 × 10^-33. A) 3.6 × 10^-12 M B) 2.2 × 10^-10 M C) 4.8 × 10^-35 M D) 2.6 × 10^-9 M E) 6.0 × 10^-19 M

Question

Quizplus · Accepted Answer

We can use the given value of Ksp to calculate the molar solubility of Al(OH)3:

Ksp = [Al3+][OH-]^3

Let x be the molar solubility of Al(OH)3 in water. Then we can write:

Ksp = (x)(3x)^3 = 27x^4
1.3 × 10^-33 = 27x^4
x = (1.3 × 10^-33 / 27)^(1/4) = 2.6 × 10^-9 M

Therefore, the correct answer is choice D.

Determine the Molar Solubility for Al(OH)3 in Pure Water

Determine the Molar Solubility for Al(OH)₃ in Pure Water