Determine the molar solubility for Cd(OH)₂ in pure water.K_sp for Cd(OH)₂ is 2.0 × 10^-14. A) 2.0 × 10^-14 M B) 1.7 × 10^-5 M C) 6.6 × 10^-8 M D) 3.5 × 10^-6 M E) 2.9 × 10^-6 M

Question

Quizplus · Accepted Answer

The Ksp expression for Cd(OH)₂ is: Cd(OH)₂(s) ⇌ Cd2+(aq) + 2OH-(aq) + S2-(aq) Ksp = [Cd2+][OH-]2[S2-] Let x be the molar solubility of Cd(OH)₂ in pure water. Then at equilibrium, the concentrations of Cd2+, OH-, and S2- in the solution will be x, 2x, and x, respectively. Substituting these values into the Ksp expression gives: Ksp = x(2x)2(x) = 4x3 Substituting Ksp = 2.0 × 10^-14 and solving for x gives: 2.0 × 10^-14 = 4x3 x = (2.0 × 10^-14 / 4)1/3 = 1.68 × 10^-5 M ≈ 1.7 × 10^-5 M. Therefore, the best choice is B.

Determine the Molar Solubility for Cd(OH)2 in Pure Water

Determine the Molar Solubility for Cd(OH)₂ in Pure Water