Given the following equation, N₂O(g)+ NO₂(g)→ 3 NO(g)ΔG°_rxn = -23.0 kJ Calculate ΔG°_rxn for the following reaction. 2 N₂O(g)+ 2 NO₂(g)→ 6 NO(g)

Question

Quizplus · Accepted Answer

The given reaction is multiplied by 2 and the coefficients are also doubled. Therefore, ΔG°rxn will also be doubled according to the equation ΔG°rxn=nΔG°f(products) - nΔG°f(reactants). So, ΔG°rxn for the new reaction will be -23.0 kJ x 2 = -46 kJ. Therefore, the correct answer is C, which is -46 kJ.

Given the Following Equation, N2O(g)+ NO2(g)→ 3 NO(g)ΔG°rxn = -23

Given the Following Equation, N₂O(g)+ NO₂(g)→ 3 NO(g)ΔG°_rxn = -23