Calculate ΔG_rxn at 298 K under the conditions shown below for the following reaction. SO₃(g) + H₂O(g) → H₂SO₄(l) ΔG°= -90.5 kJ
P(SO₃) = 0.20 atm,P(H₂O) = 0.88 atm

Question

Calculate ΔG_rxn at 298 K under the conditions shown below for the following reaction. SO₃(g)+ H₂O(g)→ H₂SO₄(l)ΔG°= -90.5 kJ P(SO₃)= 0.20 atm,P(H₂O)= 0.88 atm

Quizplus · Accepted Answer

The change in free energy under nonstandard-state conditions is given by the equation:ΔG_rxn = ΔG° + RTlnQwhere ΔG° is the standard free-energy change, R is the gas constant (8.314 J/mol·K), T is the temperature in kelvins, and Q is the reaction quotient.The reaction quotient is calculated using the partial pressures of the reactants and products:Q = P(H₂SO₄) / (P(SO₃) * P(H₂O))Since the product is a liquid, its partial pressure is 1 atm. Therefore, the reaction quotient becomes:Q = 1 / (0.20 atm * 0.88 atm) = 5.68Substituting the values into the equation for ΔG_rxn, we get:ΔG_rxn = -90.5 kJ + (8.314 J/mol·K)(298 K)ln(5.68) = -88.5 kJTherefore, the correct answer is D) -88.5 kJ.

Calculate ΔGrxn at 298 K Under the Conditions Shown Below

Calculate ΔG_rxn at 298 K Under the Conditions Shown Below