Balance the following redox reaction if it occurs in H₂SO₄.What are the coefficients in front of C₃H₈O₂and H₂SO₄ in the balanced reaction?
C₃H₈O₂(aq) + K₂Cr₂O₇(aq) → C₃H₄O₄(aq) + Cr₂(SO₄) ₃(aq)

Question

Quizplus · Accepted Answer

- To balance the equation, first, we need to identify which elements are being oxidized and reduced. We can do this by assigning oxidation states to each element in the equation. - In K₂Cr₂O₇(aq), the oxidation state of chromium (Cr) is +6, while in Cr₂(SO₄)₃(aq) it is +3. Therefore, Cr is being reduced from +6 to +3. - In C₃H₈O₂(aq), the oxidation state of sulfur (S) in HSO4 is +6, while in SO42- is +6. Therefore, S is not being oxidized or reduced. - We can balance the equation by adding coefficients to each compound so that the number of atoms of each element is equal on both sides of the equation. - The balanced equation is: 3CSO4^2- + 8HSO4^- + 2KCr2O7 -> 3H2SO4 + Cr2(SO4)3 + 2KSO4 - From the balanced equation, we can see that the coefficient in front of C₃H₈O₂ is 3 and the coefficient in front of H₂SO₄ is 8. Therefore, the answer is (D).

Balance the Following Redox Reaction If It Occurs in H2SO4

Balance the Following Redox Reaction If It Occurs in H₂SO₄