In conducting a one-way analysis of variance where the test statistic is less than the critical value, which of the following is correct?
A) Conclude that the means are not all the same and that that the Tukey-Kramer procedure should be conducted.
B) Conclude that the means are not all the same and that that the Tukey-Kramer procedure is not needed.
C) Conclude that all means are the same and that the Tukey-Kramer procedure should be conducted.
D) Conclude that all means are the same and there is no need to conduct the Tukey-Kramer procedure.

Question

Quizplus · Accepted Answer

When the test statistic in a one-way ANOVA is less than the critical value, it indicates that there is not enough evidence to reject the null hypothesis, which states that all group means are equal. Therefore, there is no need to conduct post-hoc tests like the Tukey-Kramer procedure, which are used to identify specific differences between means when the null hypothesis is rejected.

In Conducting a One-Way Analysis of Variance Where the Test