A mixture of 50.00 grams propane,C₃H₈,and 100.00 grams oxygen,O₂,is combusted.____________________is the limiting reactant and____________________ grams of____________________ is in excess.(C₃H₈ = 44.10 g/mol) C₃H₈ (g)+ 5 O₂ (g)$\rightarrow$3 CO₂ (g)+ 4 H₂O (g)

Question

Quizplus · Accepted Answer

The limiting reactant is oxygen, and 22.42 grams of propane is in excess.

A Mixture of 50 →\rightarrow→ 3 CO2 (G)+ 4 H2O (G) A)Propane;22

A Mixture of 50 $\rightarrow$ 3 CO₂ (G)+ 4 H₂O (G)
A)Propane;22