Calculate [Ba2+] when 35.00 mL of 0.2000 M EDTA is added to 50.00 mL of 0.1000 M Ba2+ in the presence of 0.1 M nitrilotriacetate. = 1.48 x 10−4.
= 0.30 for pH 10.Kf = 7.59 × 107 for BaY2−.
Correct Answer:
Verified
Q1: The reaction between Al3+ and EDTA is
Q3: Calculate [Mn2+] when 50.00 mL of 0.1000
Q4: Which statement is NOT true for auxiliary
Q5: Calculate pBa when 35.00 mL of 0.1
Q6: A_ is a reagent that protects a
Q7: Ammonia,0.10 M,is used as an auxiliary
Q8: The_ is the ability of multidentate ligands
Q9: Which is NOT an end point detection
Q10: Calculate pBa when 35.00 mL 0.1 M
Q11: For EDTA titrations the titration reaction is
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents