The metabolism of glucose can be represented by the equation C₆H₁₂O₆(s)+ 6 O₂(g)→ 6 CO₂(g)+ 6 H₂O(g)ΔH = -2.82 × 10³ kJ.How many grams of glucose must be metabolized to produce 282 kJ of energy?

Question

Quizplus · Accepted Answer

The equation shows that the metabolism of glucose releases -2.82 × 10^3 kJ of energy. To find out how many grams of glucose are needed to produce 282 kJ, we first determine the ratio of energy produced per mole of glucose. Since glucose (C6H12O6) has a molar mass of approximately 180 g/mol, and the given energy release is for the metabolism of one mole of glucose, we calculate the amount of glucose needed for 282 kJ as follows: (282 kJ / 2.82 × 10^3 kJ) * 180 g/mol = 18 g.

The Metabolism of Glucose Can Be Represented by the Equation