A piece of metal ore weighs 8.25 g.When a student places it into a graduated cylinder containing water,the liquid level rises from 21.25 mL to 26.47 mL.What is the density of the ore?
A)0)312 g/mL
B)0)633 g/mL
C)1)58 g/mL
D)3)21 g/mL

Question

Quizplus · Accepted Answer

To find the density of the ore, we need to use the formula:

density = mass/volume

We know the mass of the ore is 8.25 g. To find the volume of the ore, we need to find the volume of water displaced by the ore when it was submerged in the graduated cylinder.

The volume of water displaced is equal to the difference between the final volume and the initial volume.

Volume of water displaced = final volume - initial volume = 26.47 mL - 21.25 mL = 5.22 mL

Now, we can find the density of the ore:

density = mass/volume = 8.25 g/5.22 mL = 1.58 g/mL

Therefore, the answer is (C) 1.58 g/mL.

A Piece of Metal Ore Weighs 8