Determine the concentration of a solution prepared by diluting 25.0 mL of a stock 0.188 M Ca(NO₃)₂ solution to 150.0 mL. A)1.13 M B)0.0887 M C)0.0313 M D)0.0199 M E)0.0501 M

Question

Quizplus · Accepted Answer

Use the dilution formula: M1V1 = M2V2
M1 = 0.188 M (from the stock solution)
V1 = 25.0 mL
V2 = 150.0 mL
M2 = (M1V1)/V2 = (0.188 M x 25.0 mL)/150.0 mL = 0.0313 M
Therefore, the concentration of the diluted solution is 0.0313 M, which is choice C.

Determine the Concentration of a Solution Prepared by Diluting 25