What volume of 0.305 M AgNO₃ is required to react exactly with 155.0 mL of 0.274 M Na₂SO₄ solution? Hint: you will want to write a balanced reaction. A)581 mL B)173 mL C)345 mL D)139 mL E)278 mL

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The balanced reaction is: 2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3. Moles of Na2SO4 = 0.155 L * 0.274 M = 0.04247 mol. Moles of AgNO3 needed = 2 * 0.04247 mol = 0.08494 mol. Volume of AgNO3 = 0.08494 mol / 0.305 M = 0.278 L = 278 mL.

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