How many liters of oxygen gas can be produced at STP from the decomposition of 0.250 L of 3.00 M H₂O₂ in the reaction according to the chemical equation shown below?
2 H₂O₂(l) → 2 H₂O(l) + O₂(g)

Question

Quizplus · Accepted Answer

At STP, 1 mole of gas occupies 22.4 L. The decomposition of 0.250 L of 3.00 M H₂O₂ gives 0.750 moles of H₂O₂. According to the equation, 2 moles of H₂O₂ produce 1 mole of O₂. Therefore, 0.750 moles of H₂O₂ produce 0.375 moles of O₂, which is 0.375 x 22.4 L = 8.41 L of O₂.

How Many Liters of Oxygen Gas Can Be Produced at STP