What is the minimum energy required to decompose 765 g of PCl₃,according to the reaction below? The molar mass of PCl₃ is 137.32 g/mol and may be useful.
4 PCl₃(g) → P₄(s) + 6 Cl₂(g) ΔH°_rxn = +1207 kJ

Question

Quizplus · Accepted Answer

First, calculate the moles of PCl₃: 765 g / 137.32 g/mol = 5.57 mol. The reaction shows that 4 moles of PCl₃ require 1207 kJ. Therefore, 5.57 moles require (5.57 mol / 4 mol) × 1207 kJ = 1680.5 kJ, which is approximately 1.68 × 10³ kJ.

What Is the Minimum Energy Required to Decompose 765 G